a) The linear function that runs through the point $$ (-2 ; 3) $$ and has a gradient of $$ -\frac{2}{3} $$ b) The linear function $$ \frac{1}{2} y-x=3 $$ using the dual intercept method. c) Given $$ y=-x^{2}+6 x-5 $$. Plot the $$ x $$ and $$ y $$ intercepts, the axis of symmetry and the turning point and then link the points to form the graph.

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Hamilton Elliott · Accepted Answer

a) The linear function is $$y = -\frac{2}{3}x + \frac{5}{3}$$. b) The linear function in intercept form is $$y = 2x + 6$$, with y-intercept at (0, 6) and x-intercept at (-3, 0). c) The quadratic function $$y = -x^2 + 6x - 5$$ has x-intercepts at (1, 0) and (5, 0), y-intercept at (0, -5), axis of symmetry at $$x = 3$$, and turning point at (3, 4).

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