Long Cummings
09/02/2024 · Junior High School
For the function \( f \), use composition of functions to show that \( f^{-1} \) is as given. \( f(x)=\frac{3-x}{x}, f^{-1}(x)=\frac{3}{x+1} \) To show that \( f^{-1}(x)=\frac{3}{x+1} \), find \( \left(f^{-1} \circ f\right)(x) \) and \( \left(f \circ f^{-1}\right)(x) \) and check to see that each is \( x \). Beginning with \( \left(f^{-1} \circ f\right)(x) \). \[ \left(f^{-1} \circ f\right)(x)=\square \]
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To show that \( f^{-1}(x) = \frac{3}{x+1} \) is the inverse of \( f(x) = \frac{3-x}{x} \), we compute \( (f^{-1} \circ f)(x) \) and \( (f \circ f^{-1})(x) \). Both computations yield \( x \), confirming that \( f^{-1}(x) \) is the inverse of \( f(x) \).
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