QUESTION 24 The economizing problem is essentially one of deciding how to make the best use of a. unlimited resources to satisfy unlimited wants. b. limited resources to satisfy limited wants. d. unlimited resources to satisfy limited wants.

e) \( \$ 12500 \) invested on 10 years at \( 0.7 \% \) per month

Use the appropriate compound interest formula to find the amount that will be in each account, given the stated conditions. \( \$ 27,500 \) invested at \( 3.85 \% \) annual interest for 4 years compounded (a) daily ( \( \mathrm{n}=365 \) ); (b) continuously (a) The amount that \( \$ 27,500 \) invested at \( 3.85 \% \) annual interest for 4 years compounded daily ( \( n=365 \) ) is \( \$ \square \) (Round to the nearest cent as needed.) (b) The amount that \( \$ 27,500 \) invested at \( 3.85 \% \) annual interest for 4 years compounded continuously is \( \$ \square \) (Round to the nearest cent as needed.)

When Justin drives between Austin to Houston, he drives an average speed of 65 miles per hour. It takes 2 hour and 30 minutes for Justin to make the trip. His car averages 30 miles per gallon of gas. If gas costs \( \$ 3.45 \) per gallon, what is Justin's cost for each mile driven?

To purchase \( \$ 14,300 \) worth of machinery for her business, Christine made a down payment of \( \$ 1500 \) and took out a business loan for the rest. After 2 years of paying monthly payments of \( \$ 567.31 \), she finally paid off the loan. \( \begin{array}{ll}\text { (a) } \begin{array}{l}\text { What was the total amount Christine ended up paying for the machinery } \\ \text { (including the down payment and monthly payments)? } \\ \$ \square\end{array} \\ \text { (b) How much interest did Christine pay on the loan? }\end{array} \)

10. Suatu pinjaman obiligasi \( 4 \% \) sebesar Rp 1.000 .000 terbagi dalam 1.000 obligasi masing - masing \( R \) 1.000 dilunasi dengan anuitasselama 5 tahun. Jumlah obligasi yang diangsur padaangsuran ketiga sebanyak \( \begin{array}{lllll}\text { A. } 184 & \text { B } 192 & \text { C. } 200 & \text { D. } 208 & \text { E. } 216\end{array} \)