Paul Best
06/03/2024 · High School
5 Se sabe que a \( 40^{\circ} \mathrm{C} \) la presión de vapor del agua es 55,4 mmHg. Calcula la presión de vapor de la disolu- ción, supuesta ideal, obtenida al mezclar 1 L de agua con 200 g de sacarosa \( \left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right) \). Datos: masas atómicas: \( \mathrm{C}=12 ; \mathrm{H}=1 ; \mathrm{O}=16 ; \rho_{\text {agua }}=1 \mathrm{~g} / \mathrm{mL} \)
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La presión de vapor de la disolución de sacarosa en agua a \( 40^{\circ} \mathrm{C} \) es aproximadamente \( 54.76 \, \text{mmHg} \).
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