The formula for converting from Celsius to Fahrenheit is \( F=\frac{9}{5} \mathrm{C}+32 \). The Fahrenheit temperature of a certain city has never exceeded \( 95^{\circ} \). How would you describe this using Celsius temperature?

Consider the following function. \[ f(x)=1-x^{2 / 3} \] Find \( f(-1) \) and \( f(1) \) \( f(-1)=\square \) \( f(1)=\square \)

Which of the following is equal to \( \log \sqrt[4]{1000} \) ? ( 1 point) \( \begin{array}{l}\frac{3}{4} \\ -\frac{4}{3} \\ -\frac{3}{4}\end{array} \)

What value is equivalent to \( \log _{2} 13 \) to the nearest thousandth? Use the change of base formula to determine your answer. (1 point) 0.270 3.700 0.813 0.557

Simplify. \( 9^{\frac{3}{2}} \)

Which of the following is the value of \( \log 10^{20} \) ? (1 point) \( \frac{1}{2} \) 2 200 20