Which of the following matrices (A-E below) is the inverse matrix of: \( \left(\begin{array}{ccc}1 & 2 & -2 \\ 3 & 2 & -4 \\ -3 & 0 & 5\end{array}\right) ? \) A: \( \left(\begin{array}{ccc}-5 / 4 & 5 / 4 & 1 / 2 \\ 3 / 8 & 1 / 8 & 1 / 4 \\ -3 / 4 & 3 / 4 & 1 / 2\end{array}\right) \) B: \( \left(\begin{array}{ccc}5 / 4 & 1 / 4 & 1 / 2 \\ 3 / 8 & -3 / 8 & 1 / 4 \\ 1 / 4 & 3 / 4 & 1 / 4\end{array}\right) \) C: \( \left(\begin{array}{ccc}-5 / 4 & 1 / 4 & 1 / 4 \\ 3 / 2 & 1 / 2 & -1 / 4 \\ -3 / 4 & 1 / 4 & 1 / 2\end{array}\right) \) D: \( \left(\begin{array}{ccc}-5 / 4 & 1 / 2 & -1 / 4 \\ 1 / 4 & -1 / 2 & -1 / 4 \\ 3 / 2 & -1 / 4 & -1 / 2\end{array}\right) \) E: \( \left(\begin{array}{ccc}5 / 4 & -1 / 4 & -1 / 4 \\ 1 / 3 & 3 / 8 & 1 / 4 \\ 1 / 2 & -3 / 4 & 1 / 2\end{array}\right) \)

dation \( \log _{3}(2 x-1)=3 \)

dent Name: Which graph shows the solution of \( -6(n-1)<3 \) and \( 2(n+1)>0 \) ?

1) \( \left(4 x^{2}+5\right)\left(x^{2}-2\right)\left(x^{2}+2\right)=0 \) A) \( \left\{\frac{i \sqrt{5}}{2},-\frac{i \sqrt{5}}{2}, \sqrt{2},-\sqrt{2}, i \sqrt{2},-i \sqrt{2}\right\} \) B) \( \left\{\frac{i \sqrt{10}}{2},-\frac{i \sqrt{10}}{2}, \sqrt{2},-\sqrt{2}, i \sqrt{2},-i \sqrt{2}\right\} \) C) \( \left\{\frac{i \sqrt{15}}{3},-\frac{i \sqrt{15}}{3}, i \sqrt{3},-i \sqrt{3}, i \sqrt{2},-i \sqrt{2}\right\} \) D) \( \left\{\right. \) mult. \( \left.2, \frac{i \sqrt{5}}{2},-\frac{i \sqrt{5}}{2}, \sqrt{2},-\sqrt{2}\right\} \)

Write the expression as a single logarithm. \( 6 \log _{c} x+7 \log _{c} y-\frac{1}{3} \log _{c} z \) A. \( 6 \log _{c} x+7 \log _{c} y-\frac{1}{3} \log _{c} z=\log _{c} \frac{y^{7} z^{1 / 3}}{x^{6}} \) B. \( 6 \log _{c} x+7 \log _{c} y-\frac{1}{3} \log _{c} z=\log _{c} \frac{x^{6} y^{7}}{z^{3}} \) O. \( 6 \log _{c} x+7 \log _{c} y-\frac{1}{3} \log _{c} z=\log _{c} \frac{x^{6} y^{7}}{z^{1 / 3}} \) O. \( 6 \log _{c} x+7 \log _{c} y-\frac{1}{3} \log _{c} z=\log _{c} \frac{x^{6} z^{1 / 3}}{y^{7}} \)

The following function is given. \( f(x)=3 x^{3}-7 x^{2}-75 x+175 \) a. List all rational zeros that are possible according to the Rational Zero Theorem. Choose the correct answer below.