Schultz Wells
05/09/2023 · Primary School
A person invest in an account with interest compounded continuously according to the formula \( A=f(t)=8200 e^{0.059 t} \) where \( A \) is the amount in the account and \( t \) is in years. Find \( f(0)=\$ 8200 \) To the nearest cent, find the amount in the account after 8 years. \( \$ \) To the nearest tenth of a year, determine how long it will take for the investment to grow to \( \$ 10100 \).
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The amount in the account after 8 years is approximately \$13125.60. It will take approximately 3.6 years for the investment to grow to \$10100.
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