Jude says that the expression \( \frac{a}{5} \) has no terms because there are no plus or minus signs. Explain if her reasoning is correct. Choose the correct answer below. A. Jude's reasoning is not correct. Each variable in an expression is a term. The expression has one term, a. B. Jude's reasoning is not correct. The expression has one term, \( \frac{a}{5} \). It is the only term because there are no other C. Jude is correct. The expression has no terms because there are no plus or minus signs. D. Jude is incorrect. The expression has two terms, a and 5 .

(ס) \( \frac{4(a-9)}{36(9-a) x^{3}} \)

Given that \( g(x)=\sqrt{\frac{2 x+3}{5 x+6}} \), find \( g^{-1}(x) \) \( g^{-1}(x)=x^{2}-3 x \)

1.Решить уравнение: \( \begin{array}{lll}\text { a) } \sqrt{x+3}=\sqrt{5-x} & \text { б) } \quad \sqrt{12+3 x}=2 & \text { в) } \quad x=1+\sqrt{x+11}\end{array} \)

Jika \( \left(\begin{array}{cc}-2 & 2 \\ 5 & y\end{array}\right)\left(\begin{array}{ll}5 & 3 \\ x & 4\end{array}\right)=\left(\begin{array}{cc}-6 & 2 \\ 27 & 19\end{array}\right) \), cari nilai \( x \) dan \( y \). If \( \left(\begin{array}{cc}-2 & 2 \\ 5 & y\end{array}\right)\left(\begin{array}{ll}5 & 3 \\ x & 4\end{array}\right)=\left(\begin{array}{cc}-6 & 2 \\ 27 & 19\end{array}\right) \), find the value of \( x \) and \( y \).

Resuelve la desigualdad de valor absoluto: \(|x| < 3\)