Three textbooks have a mean weight of 16.40 pounds, with a standard deviation of 2.20 pounds. A cardboard shipping box has a mean weight of 0.74 pounds with a standard deviation of 0.13 pounds. What are the mean and standard deviation of the weight of a shipping box packed with three textbooks? Mean = [?] S.D. \( \quad \) [ \( ] \)

2.50. Uz jautājumu "Cik minūtes nepieciešamas, lai skolēns no mājām atnāktu uz skolu?" 60 pirmo klašu skolēnu vecāki atbildēja šādi: \( 5 ; 4 ; 28 ; 28 ; 11 ; 17 ; 17 ; 10 ; 19 ; 27 ; 22 ; 9 ; 26 ; 5 ; 19 ; 21 ; 21 ; 21 ; 7 ; 2 ; 8 ; 14 ; 5 ; 20 ; 13 ; 24 ; 14 ; 15 \); \( 3 ; 29 ; 13 ; 13 ; 22 ; 17 ; 2 ; 26 ; 30 ; 14 ; 8 ; 1 ; 20 ; 15 ; 16 ; 21 ; 20 ; 18 ; 25 ; 8 ; 12 ; 24 ; 9 ; 27 ; 8 ; 9 ; 13 ; 2 ; \) \( 8 ; 19 ; 16 ; 23 \). a) Sakārto datus tabulā, grupējot tos no 1 līdz \( 5 ; \) no 6 līdz 10; no 11 līdz 15; no 16 līdz 20; 21 un vairāk minūtes! b) Nosaki datu modu! c) Aprēkini katras datu grupas relatīvo biežumu! d) Izmantojot tabulas datus, uzzīmē relatīvo biežumu stabinu diagrammu!

Baseball regression line prediction: Suppose the regression line for the number of runs scored in a season, \( y \), is given by \( \hat{y}=-730+4300 x \), where \( x \) is the team's batting average. a. For a tearn with a batting average of 0.235 , find the expected number of runs scored in a season. Round your answer to the nearest whole number. b. If we can expect the number of runs scored in a scason is 480 , then what is the assumed team's batting average? Round your onswer to three deeima! places.

A regression was run to determine if there is a relationship between hours of TV watched per day \( (\mathrm{x}) \) and number of situps a person can do \( (y) \). The results of the regression were: \( \begin{array}{l}\mathrm{y}=\mathrm{ax}+\mathrm{h} \\ \mathrm{a}=2.389 \\ \mathrm{~b}=37.535 \\ \mathrm{r}^{2}=0.412164 \\ \mathrm{r}=-0.642\end{array} \) Use this to predict the number of situps a person who watches 0.5 hours of TV can do (ta one decimal place)

How do you identify the relationship between two variables in a scatter plot?

Why is data collection appropriate for this two-sample proportion procedure? Because the order of applying the two treatments to each doctor was randomized in this matched pairs design. Because two separate simple random samples were taken-one from each population. Because the doctors were randomly allocated to the two treatments (aspirin and placebo).