\begin{tabular}{l} (b) Using the formula \( \operatorname{Sin} 2 A=2 \operatorname{Sin} A \operatorname{Cos} A \) \\ solve the equation \( \sin 2 x-\cos x=0 \) \\ in the interval \( 0^{\circ} \leq x \leq 360^{\circ} \) \\ \hline\end{tabular}

Corvert the following angle from degrees to radians. Express your answer in simplest form.

Find all solutions of the equation \( 2 \cos x-1=0 \). The answer is \( A+B k \pi \) and \( C+D k \pi \) where \( k \) is any integer, \( 0<A<C<2 \pi \), \( A=\square, D=\square \) \( C=\square \)

Find an angle \( \theta \) coterminal to \( -555^{\circ} \), where \( 0^{\circ} \leq \theta<360^{\circ} \)

Which is the correct identity for cos? \( \cos \theta=\frac{h}{a} \) \( \cos =\frac{h}{a} \) \( \cos \theta=\frac{a}{h} \) \( \cos =\frac{a}{h} \)

\( \frac { 4 \sin \frac { \alpha } { 2 } \cos \frac { \alpha } { 2 } } { \tan \frac { \alpha } { 2 } } - 1 \)