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2. Find the first derivative for the following function. \[ f(x)=10 x^{10}-2 \sqrt{x}+3.31 \] \[ f \]

Ask by Whittaker Luna. in the United States
Feb 24,2025

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Answer

The first derivative of the function \( f(x) = 10x^{10} - 2\sqrt{x} + 3.31 \) is: \[ f'(x) = 100x^{9} - \frac{1}{\sqrt{x}} \]

Solution

To differentiate the function f(x) = 10x^(10) - 2√x + 3.31, follow these steps: 1. Rewrite √x as x^(1/2). 2. Differentiate each term: - For 10x^(10): The derivative is 10 * 10x^(9) = 100x^(9). - For -2x^(1/2): The derivative is -2 * (1/2)x^(-1/2) = -x^(-1/2). - The derivative of the constant 3.31 is 0. 3. Combine the derivatives: f '(x) = 100x^(9) - x^(-1/2) So, the first derivative is: f '(x) = 100x^(9) - 1/√x

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The first derivative of the function \( f(x) = 10x^{10} - 2\sqrt{x} + 3.31 \) is calculated by applying the power rule and the derivative of the square root function. For the term \( 10x^{10} \), the derivative is \( 100x^9 \). The term \( -2\sqrt{x} \) can be rewritten as \( -2x^{1/2} \), and its derivative results in \( -1x^{-1/2} \) or \( -\frac{1}{\sqrt{x}} \). The constant \( 3.31 \) disappears. Thus, the first derivative is: \[ f'(x) = 100x^9 - \frac{1}{\sqrt{x}}. \] This snazzy formula shows how quickly your function is changing at any point along its x-axis! Everything about calculus is based on understanding how functions behave, and that’s super useful in real life. For instance, if you’re designing a roller coaster, knowing how steep the hills will be as the speed changes at different points can make all the difference in safety and excitement! So, next time you hop on a ride, remember there’s a bit of calculus behind the thrills!

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