c) \( \left(x+\frac{1}{3}\right)\left(x-\frac{1}{3}\right) \)

This expression can be simplified using the difference of squares formula, which states that \( (a + b)(a - b) = a^2 - b^2 \). Here, we can treat \( a = x \) and \( b = \frac{1}{3} \). Applying this gives us: \[ \left(x + \frac{1}{3}\right)\left(x - \frac{1}{3}\right) = x^2 - \left(\frac{1}{3}\right)^2 = x^2 - \frac{1}{9} \] Now you have a simpler expression, showcasing how powerful algebraic identities can be for simplifying products! You can find similar instances in real life as well! For example, when constructing a structure that involves parabolic shapes, engineers often use difference of squares to calculate dimensions accurately. It’s fascinating how these mathematical concepts translate into practical applications that shape our world!