Question
upstudy study bank question image url

A golf ball is hit with an initial velocity of 150 feet per second at an inclination of \( 45^{\circ} \) to the horizontal. In physics, it is established that the height h of the golf ball is given by the function \[ \mathrm{h}(\mathrm{x})=\frac{-32 \mathrm{x}^{2}}{150^{2}}+\mathrm{x} \text {, } \] where x is the horizontal distance that the golf ball has traveled. Complete parts (a) through (g). (a) Determine the height of the golf ball after it has traveled 100 feet. \( \mathrm{h}=\square \) feet (Round to two decimal places as needed.)

Ask by Park Alexander. in the United States
Feb 19,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The height of the golf ball after it has traveled 100 feet is approximately 85.78 feet.

Solution

To find the height of the golf ball after it has traveled 100 feet, we need to substitute the value of \( x = 100 \) into the given function \( h(x) = \frac{-32x^2}{150^2} + x \) and calculate the result. Given function: \( h(x) = \frac{-32x^2}{150^2} + x \) Substitute \( x = 100 \) into the function: \[ h(100) = \frac{-32(100)^2}{150^2} + 100 \] Now, let's calculate the height of the golf ball after it has traveled 100 feet. Calculate the value by following steps: - step0: Calculate: \(\frac{-32\times 100^{2}}{150^{2}}+100\) - step1: Reduce the fraction: \(-\frac{128}{3^{2}}+100\) - step2: Evaluate the power: \(-\frac{128}{9}+100\) - step3: Reduce fractions to a common denominator: \(-\frac{128}{9}+\frac{100\times 9}{9}\) - step4: Transform the expression: \(\frac{-128+100\times 9}{9}\) - step5: Multiply the numbers: \(\frac{-128+900}{9}\) - step6: Add the numbers: \(\frac{772}{9}\) The height of the golf ball after it has traveled 100 feet is approximately 85.78 feet.

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

Beyond the Answer

To determine the height of the golf ball after it has traveled 100 feet, we'll use the function provided: \[ \mathrm{h}(\mathrm{x})=\frac{-32 \mathrm{x}^{2}}{150^{2}}+\mathrm{x} \] Substituting \( x = 100 \) into the equation: \[ \mathrm{h}(100) = \frac{-32(100)^2}{150^2} + 100 \] Calculating the \( \frac{-32(100)^2}{150^2} \): \[ = \frac{-32 \times 10000}{22500} = \frac{-320000}{22500} \approx -14.22 \] So we have: \[ \mathrm{h}(100) = -14.22 + 100 = 85.78 \] Thus, the height of the golf ball after it has traveled 100 feet is: \(\mathrm{h} \approx 85.78 \) feet.

Related Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy