A golf ball is hit with an initial velocity of 150 feet per second at an inclination of \( 45^{\circ} \) to the horizontal. In physics, it is established that the height h of the golf ball is given by the function \[ \mathrm{h}(\mathrm{x})=\frac{-32 \mathrm{x}^{2}}{150^{2}}+\mathrm{x} \text {, } \] where x is the horizontal distance that the golf ball has traveled. Complete parts (a) through (g). (a) Determine the height of the golf ball after it has traveled 100 feet. \( \mathrm{h}=\square \) feet (Round to two decimal places as needed.)
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Beyond the Answer
To determine the height of the golf ball after it has traveled 100 feet, we'll use the function provided: \[ \mathrm{h}(\mathrm{x})=\frac{-32 \mathrm{x}^{2}}{150^{2}}+\mathrm{x} \] Substituting \( x = 100 \) into the equation: \[ \mathrm{h}(100) = \frac{-32(100)^2}{150^2} + 100 \] Calculating the \( \frac{-32(100)^2}{150^2} \): \[ = \frac{-32 \times 10000}{22500} = \frac{-320000}{22500} \approx -14.22 \] So we have: \[ \mathrm{h}(100) = -14.22 + 100 = 85.78 \] Thus, the height of the golf ball after it has traveled 100 feet is: \(\mathrm{h} \approx 85.78 \) feet.
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