$$ \left\lvert\, \begin{array}{l}\frac{x^{2}-7 x+12}{x-3}=\square \ ext { (Simplify your answer.) }\end{array} ight. $$

Question

$$ \left\lvert\, \begin{array}{l}\frac{x^{2}-7 x+12}{x-3}=\square \ 	ext { (Simplify your answer.) }\end{array}ight. $$

UpStudy AI · Accepted Answer

1. Factor the numerator:
   $$
   x^2 - 7x + 12 = (x - 3)(x - 4)
   $$

2. Substitute the factored form into the expression:
   $$
   \frac{(x - 3)(x - 4)}{x - 3}
   $$

3. Cancel the common factor $$(x - 3)$$, keeping in mind that $$x \neq 3$$:
   $$
   = x - 4
   $$

Thus, the simplified expression is $$x - 4$$ with the condition $$x \neq 3$$.
The simplified expression is $$x - 4$$, provided that $$x$$ is not equal to 3.

\( \left\lvert\, \begin{array}{l}\frac{x^{2}-7 x+12}{x-3}=\square \\ \text { (Simplify your answer.) }\end{array}\right. \)

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