Question
In a genetics class, 6 students have GREEN eyes, 3 students have BLUE eyes, and 11 have HAZEL eyes. If a single student is picked at random, what is the probability that their eyes are GREEN or HAZEL? Provide the final answer as a simplified fraction.
Ask by Malone Hobbs. in the United States
Feb 25,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The probability is \( \frac{17}{20} \).
Solution
There are a total of 6 + 3 + 11 = 20 students. The number of students with green or hazel eyes is 6 + 11 = 17. So, the probability of picking a student with green or hazel eyes is 17/20.
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Simplify this solution Extra Insights
To find the probability that a randomly selected student has GREEN or HAZEL eyes, first we need to determine the total number of students. There are 6 students with GREEN eyes, 3 with BLUE eyes, and 11 with HAZEL eyes. Thus, the total number of students is: 6 (GREEN) + 3 (BLUE) + 11 (HAZEL) = 20 students. Now, we'll calculate how many students have either GREEN or HAZEL eyes: 6 (GREEN) + 11 (HAZEL) = 17 students. Now, we can find the probability: Probability = (Number of students with GREEN or HAZEL eyes) / (Total number of students) = 17 / 20. The fraction 17/20 is already in its simplest form. Therefore, the final answer is: \[ \frac{17}{20} \]
