\( \text { 41) Write an explicit formula for the recursive formula. } \\ a_{1}=16, a_{n}=4 a_{n-1}, n \geq 2 \\ a_{1} \ \ a_{n}= \)
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To write an explicit formula for the recursive sequence where \(a_1 = 16\) and \(a_n = 4a_{n-1}\) for \(n \geq 2\), we can start by observing the pattern for the first few terms: - \(a_1 = 16\) - \(a_2 = 4 \times 16 = 64\) - \(a_3 = 4 \times 64 = 256\) From this pattern, we can infer that each term is multiplied by 4, leading to \(a_n = 16 \cdot 4^{n-1}\). There you have it: \(a_n = 16 \cdot 4^{n-1}\) for \(n \geq 1\). By identifying the explicit formula, you’re providing a shortcut to find any term in this sequence without having to calculate all the previous numbers. It's a powerful tool for sequences where iterative calculations can become cumbersome. Enjoy unraveling more sequences!