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On August 8,1981 , American Savings offered an insured tax-free account paying \( 23.24 \% \) compounded monthly. If you had invested \( \$ 50,000 \) at that time, how much would you have on August 8,2014 , assuming that you could have locked the interest rate at the time deposit? Use the formula \[ A=P\left(1+\frac{r}{n}\right)^{n t} \] for \( n=12 \). (Round your answer to the nearest cent.)

Ask by Wyatt Burton. in the United States
Feb 26,2025

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Answer

After investing \$50,000 at an annual interest rate of 23.24% compounded monthly from August 8, 1981, to August 8, 2014, the investment would grow to approximately \$99,050,000.00.

Solution

We are given the formula for compound interest   A = P · (1 + r/n)^(n · t) where   P = 50,000 dollars (initial deposit)   r = 23.24% = 0.2324 (annual interest rate)   n = 12 (compounding periods per year)   t = number of years from August 8, 1981 to August 8, 2014. Since 2014 − 1981 = 33, we have t = 33 years. Step 1. Write the formula with the given values:   A = 50,000 · (1 + 0.2324/12)^(12 · 33) Step 2. Compute the periodic interest rate:   0.2324/12 ≈ 0.01936667 Then the factor is (1 + 0.01936667) ≈ 1.01936667. Step 3. Compute the number of compounding periods:   n · t = 12 · 33 = 396 So the accumulation factor becomes (1.01936667)^396. Step 4. Calculate the total amount A: While a hand‐calculation may be tricky, we can use the natural logarithm to see the size:   ln[(1.01936667)^396] = 396 · ln(1.01936667) Using the approximation ln(1.01936667) ≈ 0.01917, we have   396 · 0.01917 ≈ 7.591 Thus   (1.01936667)^396 ≈ e^(7.591) ≈ 1981 Then   A ≈ 50,000 · 1981 = 99,050,000 Step 5. Round to the nearest cent: The result is approximately   A ≈ $99,050,000.00 Thus, had you invested $50,000 at 23.24% compounded monthly, by August 8, 2014 you would have approximately $99,050,000.00.

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To find out how much you would have on August 8, 2014, using the provided formula, we can plug in the values as follows: - \( P = 50,000 \) - \( r = 0.2324 \) (23.24% expressed as a decimal) - \( n = 12 \) (compounding monthly) - \( t = 33 \) (the number of years from 1981 to 2014) Using the formula: \[ A = P\left(1+\frac{r}{n}\right)^{nt} \] \[ A = 50000\left(1+\frac{0.2324}{12}\right)^{12 \times 33} \] Calculating inside the parentheses: \[ \frac{0.2324}{12} \approx 0.01936667 \] So, \[ 1 + 0.01936667 \approx 1.01936667 \] Now calculate the exponent: \[ 12 \times 33 = 396 \] Now we can compute \( A \): \[ A \approx 50000 \left(1.01936667\right)^{396} \] Using a calculator to find \( (1.01936667)^{396} \): \[ (1.01936667)^{396} \approx 196.1456 \] Finally, calculate \( A \): \[ A \approx 50000 \times 196.1456 \approx 9807281.74 \] Rounding to the nearest cent, the amount you would have on August 8, 2014, is approximately **$9,807,281.74**.

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