How many cubic feet of concrete are needed to pour 4 cylindrical pillars 6 feet high with a diameter of 0.75 feet? Round final answer to the nearest thousandth.

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Let the radius of each cylindrical pillar be

$$
r = \frac{0.75}{2} = 0.375 \text{ feet.}
$$

The volume $$V$$ of one cylinder with height $$h = 6$$ feet is given by

$$
V = \pi r^2 h.
$$

Substitute the values:

$$
V = \pi (0.375)^2 (6).
$$

First, compute

$$
(0.375)^2 = 0.140625.
$$

Then,

$$
6 \times 0.140625 = 0.84375.
$$

So, the volume of one pillar is

$$
V = \pi \times 0.84375 \approx 2.6516 \text{ cubic feet.}
$$

Since there are 4 pillars, the total volume is

$$
V_{\text{total}} = 4 \times 2.6516 \approx 10.6064 \text{ cubic feet.}
$$

Rounded to the nearest thousandth, the total volume is

$$
\boxed{10.606} \text{ cubic feet.}
$$
To find the total cubic feet of concrete needed for 4 cylindrical pillars: 1. **Calculate the radius** of each pillar: $$ r = \frac{0.75}{2} = 0.375 \text{ feet} $$ 2. **Determine the volume of one pillar** using the formula for the volume of a cylinder: $$ V = \pi r^2 h = \pi \times (0.375)^2 \times 6 $$ $$ V \approx \pi \times 0.140625 \times 6 \approx 2.6516 \text{ cubic feet} $$ 3. **Calculate the total volume for all pillars**: $$ V_{\text{total}} = 4 \times 2.6516 \approx 10.6064 \text{ cubic feet} $$ 4. **Round the final answer** to the nearest thousandth: $$ \boxed{10.606} \text{ cubic feet} $$

How many cubic feet of concrete are needed to pour 4 cylindrical pillars 6 feet high with a diameter of 0.75 feet? Round final answer to the nearest thousandth.

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