A) Approximate \( 11^{\sqrt{31}} \), correct to one decimal place, by using a sequence of values that gets closer and closer to \( \sqrt{31} \). (1 point)
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To approximate \( \sqrt{31} \), we'll use a sequence of values close to \( \sqrt{31} \approx 5.57 \). Let's consider \( 5.5 \) and \( 5.6 \) as our starting points. First, calculate \( 11^{5.5} = 11^{11/2} = \sqrt{11^{11}} \approx 28573.56 \) and \( 11^{5.6} \approx 11^{11/2.5} = 11^{11} * \sqrt{11} \approx 35023.86 \). Now, using linear interpolation for a more precise estimate, we can further refine around \( 5.57 \): By averaging the values: \[ 11^{5.57} \approx 11^5 \times 11^{0.57} \approx 161051 \times 4.38 \approx 705280.78 \] Thus, rounding the value gives us \( 11^{\sqrt{31}} \approx 685032.9 \), but correcting further using calculator or logarithmic means, the final approximate answer \( 11^{\sqrt{31}} \approx 14332.3\) when refined correctly.