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169. \( M(2,-1) \) нуқта берилган абсциссалар ўқи нисбатан, ординаталар ўқга нисбатан, координат лар бошига нисбатан, координата бурчакларининг би сектрисаларига нисбатан берилган нуқтага симметр бўлган нуқталарни ясанг. Бу нуқталарнинг координат

Ask by Osborne Willis. in Uzbekistan
Oct 31,2024

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Answer

- Abscissalar o'qi bo'yicha: \( (2, 1) \) - Ordinatalar o'qi bo'yicha: \( (-2, -1) \) - Koordinatalar boshiga nisbatan: \( (-2, 1) \) - Burchaklar bisektorisiga nisbatan: \( (-1, -1) \)

Solution

Berilgan nuqta \( M(2, -1) \) bo'lib, biz ushbu nuqtaning turli o'q va burchaklar bo'yicha simmetrik nuqtalarini topishimiz kerak. 1. **Abscissalar o'qi (x-o'qi) bo'yicha simmetrik nuqta:** Abscissalar o'qi bo'yicha simmetrik nuqta nuqtaning y koordinatasini o'zgartirish orqali topiladi. \[ M'(2, 1) \] 2. **Ordinatalar o'qi (y-o'qi) bo'yicha simmetrik nuqta:** Ordinatalar o'qi bo'yicha simmetrik nuqta nuqtaning x koordinatasini o'zgartirish orqali topiladi. \[ M''(-2, -1) \] 3. **Koordinatalar boshiga (0,0) nisbatan simmetrik nuqta:** Koordinatalar boshiga nisbatan simmetrik nuqta nuqtaning har ikkala koordinatasini ham o'zgartirish orqali topiladi. \[ M'''(-2, 1) \] 4. **Koordinata burchaklarining bisektorisiga nisbatan simmetrik nuqta:** Burchaklar bisektorisiga nisbatan simmetrik nuqtani topish uchun, nuqtaning x va y koordinatalarini tenglashtirish kerak. \[ M''''(-1, -1) \] Natijada, berilgan nuqtaning simmetrik nuqtalari quyidagilar: - Abscissalar o'qi bo'yicha: \( (2, 1) \) - Ordinatalar o'qi bo'yicha: \( (-2, -1) \) - Koordinatalar boshiga nisbatan: \( (-2, 1) \) - Burchaklar bisektorisiga nisbatan: \( (-1, -1) \)

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