9. $$ \frac{7}{3} x+1=\frac{17}{3} $$ (50) 11. $$ 7 x+1-x=19 $$ (50) *13. $$ \frac{4}{x}=\frac{2.8}{5.6} $$ (25, 44) 15. $$ \sqrt{50} $$

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**9. Solve: $$ \frac{7}{3} x + 1 = \frac{17}{3} $$**

1. Subtract $$1$$ from both sides. To combine with a common denominator, write $$1$$ as $$\frac{3}{3}$$:
   $$
   \frac{7}{3} x = \frac{17}{3} - \frac{3}{3} = \frac{14}{3}
   $$
2. Multiply both sides by the reciprocal of $$\frac{7}{3}$$, which is $$\frac{3}{7}$$:
   $$
   x = \frac{14}{3} \cdot \frac{3}{7} = \frac{14}{7} = 2
   $$

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**11. Solve: $$ 7x + 1 - x = 19 $$**

1. Combine like terms:
   $$
   7x - x = 6x, \quad \text{so the equation becomes} \quad 6x + 1 = 19
   $$
2. Subtract $$1$$ from both sides:
   $$
   6x = 18
   $$
3. Divide by $$6$$:
   $$
   x = 3
   $$

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**13. Solve: $$ \frac{4}{x} = \frac{2.8}{5.6} $$**

1. Simplify the fraction on the right:
   $$
   \frac{2.8}{5.6} = \frac{28}{56} = \frac{1}{2}
   $$
2. The equation becomes:
   $$
   \frac{4}{x} = \frac{1}{2}
   $$
3. Cross-multiply:
   $$
   4 \cdot 2 = x \quad \Longrightarrow \quad x = 8
   $$

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**15. Simplify: $$ \sqrt{50} $$**

1. Factor $$50$$ as $$25 \times 2$$:
   $$
   \sqrt{50} = \sqrt{25 \cdot 2}
   $$
2. Apply the property $$\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}$$:
   $$
   \sqrt{50} = \sqrt{25} \cdot \sqrt{2} = 5\sqrt{2}
   $$
**9. $$ x = 2 $$** **11. $$ x = 3 $$** **13. $$ x = 8 $$** **15. $$ \sqrt{50} = 5\sqrt{2} $$**

9. \( \frac{7}{3} x+1=\frac{17}{3} \) (50) 11. \( 7 x+1-x=19 \) (50) *13. \( \frac{4}{x}=\frac{2.8}{5.6} \) (25, 44) 15. \( \sqrt{50} \)

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