9. \( \frac{7}{3} x+1=\frac{17}{3} \) (50) 11. \( 7 x+1-x=19 \) (50) *13. \( \frac{4}{x}=\frac{2.8}{5.6} \) (25, 44) 15. \( \sqrt{50} \)
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To solve the equation \( \frac{7}{3} x + 1 = \frac{17}{3} \), start by isolating the \( x \) term by subtracting 1 from both sides. This gives you \( \frac{7}{3} x = \frac{17}{3} - 1 \), or \( \frac{7}{3} x = \frac{14}{3} \). Multiplying both sides by \( \frac{3}{7} \) results in \( x = 2 \). Voilà, you have your answer! Next, for \( 7x + 1 - x = 19 \), combine like terms to get \( 6x + 1 = 19 \). Subtract 1 from both sides to find \( 6x = 18 \), and divide by 6 to solve for \( x = 3 \). Easy peasy!