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A casino hotel manager has approximated demand for two-room suites to be \( p=3000-\frac{q^{2}}{24} \), where \( p \) is the price (in dollars) and \( q \) is the quantity demanded. Use implicit differentiation to find and interpret \( \frac{d q}{d p} \) when \( q=4 \). Choose the correct answer below and fill in the answer box to complete your answer. A. \( \frac{d q}{d p}=\square \), which means that if the price is increased by \( \$ 1 \), the quantity demanded decreases by approximately \( \left|\frac{d q}{d p}\right| \) suites. B. \( \frac{d q}{d p}=\square \), which means that if the price is increased by \( \$ 1 \), the quantity demanded increases by approximately \( \left|\frac{d q}{d p}\right| \) suites.

Ask by Malone Macdonald. in the United States
Mar 12,2025

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\( \frac{dq}{dp} = -3 \), which means that if the price increases by \$1, the quantity demanded decreases by approximately 3 suites.

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To find \(\frac{dq}{dp}\) using implicit differentiation, we start with the demand equation: \( p = 3000 - \frac{q^{2}}{24} \). Taking the derivative with respect to \( p \): 1. Rearranging gives \( q^{2} = 24(3000 - p) \). 2. Implicitly differentiating \( p \) with respect to \( q \): \[ \frac{dp}{dq} = -\frac{q}{12}. \] 3. Inverting this to find \(\frac{dq}{dp}\): \[ \frac{dq}{dp} = -\frac{12}{q}. \] Now, substituting \( q = 4 \): \[ \frac{dq}{dp} = -\frac{12}{4} = -3. \] Thus, we find that \( \frac{dq}{dp} = -3 \). A. \( \frac{dq}{dp} = -3 \), which means that if the price is increased by \( \$ 1 \), the quantity demanded decreases by approximately \( 3 \) suites.

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