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Escribe dosproblema que se resuelva planteando la proporción dada en cada caso, \( \begin{array}{ll}-\frac{4}{1600}=\frac{17}{x} & \text { (b. } \frac{50}{x}=\frac{3}{48} \\ \text { - } \frac{7}{12}=\frac{x}{30} & \text { d. } \frac{5}{38000}=\frac{2}{x}\end{array} \)

Ask by Parsons Wilson. in Colombia
Mar 15,2025

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### Problema 1 Resolver la proporción: \[ -\frac{4}{1600} = \frac{17}{x} \] **Solución:** \[ x = -6800 \] --- ### Problema 2 Resolver la proporción: \[ \frac{50}{x} = \frac{3}{48} \] **Solución:** \[ x = 800 \] --- ### Problema 3 Resolver la proporción: \[ -\frac{7}{12} = \frac{x}{30} \] **Solución:** \[ x = -\frac{35}{2} \] --- ### Problema 4 Resolver la proporción: \[ \frac{5}{38000} = \frac{2}{x} \] **Solución:** \[ x = 15200 \]

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Para resolver el primer problema, \(-\frac{4}{1600}=\frac{17}{x}\), puedes multiplicar en cruz. Así, obtienes \(-4x = 17 \cdot 1600\). Simplificando, te lleva a encontrar el valor de \(x\) que resulta ser \(-6800\). Para el segundo, \(\frac{50}{x}=\frac{3}{48}\), nuevamente multiplicas en cruz. Esto te da como resultado: \(50 \cdot 48 = 3x\). Al despejar \(x\), llegas a que \(x = 800\). ¡Y así, la proporción se convierte en un juego de matemáticas!

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