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LeSSOn20 3.7 The chain rule: Probien (1 point) Find the derivative of \( y \) using the appropriate combination of rules. \( y=(9 x+4)^{\frac{1}{2}} \) \( y^{\prime}=\square \) Preview My Answers Submit Answers

Ask by Huang Harper. in the United States
Mar 09,2025

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Answer

\( y' = \frac{9}{2} (9x+4)^{-\frac{1}{2}} \)

Solution

1. Identify the outer function and the inner function: - Outer function: \( u^{\frac{1}{2}} \) where \( u = 9x+4 \) - Inner function: \( u = 9x + 4 \) 2. Differentiate the outer function with respect to \( u \): \[ \frac{d}{du}\left(u^{\frac{1}{2}}\right) = \frac{1}{2} u^{-\frac{1}{2}} \] 3. Differentiate the inner function \( u = 9x + 4 \) with respect to \( x \): \[ \frac{du}{dx} = 9 \] 4. Apply the chain rule by multiplying the derivatives: \[ y' = \frac{1}{2} u^{-\frac{1}{2}} \cdot 9 = \frac{9}{2} (9x+4)^{-\frac{1}{2}} \] 5. The derivative is: \[ y' = \frac{9}{2} (9x+4)^{-\frac{1}{2}} \]

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To find the derivative of \( y = (9x + 4)^{\frac{1}{2}} \), we can apply the chain rule. The outer function is the square root, and the inner function is \( 9x + 4 \). The derivative of the outer function, \( u^{\frac{1}{2}} \), is \( \frac{1}{2} u^{-\frac{1}{2}} \), and for the inner function \( u = 9x + 4 \), its derivative is \( 9 \). So, using the chain rule: \[ y' = \frac{1}{2}(9x + 4)^{-\frac{1}{2}} \cdot 9 = \frac{9}{2(9x + 4)^{\frac{1}{2}}} \] Thus, the derivative \( y' = \frac{9}{2(9x + 4)^{\frac{1}{2}}} \).

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