Question
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Find the standard deviation for the following group of data items. \( 6,11,11,19 \) The standard deviation is approximately (Round to two decimal places as needed.)

Ask by Rogers Peterson. in the United States
Feb 26,2025

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Answer

The standard deviation is approximately 4.66.

Solution

Step 1. Find the mean.   Mean = (6 + 11 + 11 + 19) / 4 = 47 / 4 = 11.75 Step 2. Find the deviation of each value from the mean and then square those deviations.   For 6:  (6 – 11.75)² = (–5.75)² = 33.0625   For 11:  (11 – 11.75)² = (–0.75)² = 0.5625   For 11:  (11 – 11.75)² = (–0.75)² = 0.5625   For 19:  (19 – 11.75)² = (7.25)² = 52.5625 Step 3. Sum the squared deviations.   Total = 33.0625 + 0.5625 + 0.5625 + 52.5625 = 86.75 Step 4. Divide by the number of data items to get the variance (since this is the entire group, we use N, not N – 1).   Variance = 86.75 / 4 = 21.6875 Step 5. Take the square root of the variance to find the standard deviation.   Standard deviation = √21.6875 ≈ 4.66 Thus, the standard deviation is approximately 4.66.

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To calculate the standard deviation, first find the mean: \[ \text{Mean} = \frac{6 + 11 + 11 + 19}{4} = \frac{47}{4} = 11.75 \] Next, calculate the squared differences from the mean: \[ (6 - 11.75)^2 = (-5.75)^2 = 33.0625 \] \[ (11 - 11.75)^2 = (-0.75)^2 = 0.5625 \] \[ (11 - 11.75)^2 = (-0.75)^2 = 0.5625 \] \[ (19 - 11.75)^2 = (7.25)^2 = 52.5625 \] Now sum these squared differences: \[ 33.0625 + 0.5625 + 0.5625 + 52.5625 = 86.75 \] To find the variance, divide by the number of data items (n = 4): \[ \text{Variance} = \frac{86.75}{4} = 21.6875 \] Finally, the standard deviation is the square root of the variance: \[ \text{Standard Deviation} \approx \sqrt{21.6875} \approx 4.65 \] So, the standard deviation is approximately \(4.65\) (rounded to two decimal places).

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