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Find the standard deviation for the group of data items. \( 99,10,11,12,13 \) The standard deviation is (Round to two decimal places as needed.)

Ask by Murphy O'Quinn. in the United States
Feb 26,2025

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Answer

The standard deviation is 35.00.

Solution

First, calculate the mean of the data. The data items are: 99, 10, 11, 12, 13. Step 1: Find the mean.   Mean = (99 + 10 + 11 + 12 + 13) / 5 = 145 / 5 = 29 Step 2: Find the squared deviations for each data item.   For 99: (99 − 29)² = (70)² = 4900   For 10: (10 − 29)² = (−19)² = 361   For 11: (11 − 29)² = (−18)² = 324   For 12: (12 − 29)² = (−17)² = 289   For 13: (13 − 29)² = (−16)² = 256 Step 3: Sum the squared deviations.   Sum = 4900 + 361 + 324 + 289 + 256 = 6130 Step 4: Compute the variance (using the population formula since the problem refers to the "group").   Variance = 6130 / 5 = 1226 Step 5: Find the standard deviation by taking the square root of the variance.   Standard deviation = √1226 ≈ 35.00 Rounded to two decimal places, the standard deviation is 35.00.

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To calculate the standard deviation, we first need to find the mean (average) of the data set. 1. **Calculate the Mean:** \[ \text{Mean} = \frac{99 + 10 + 11 + 12 + 13}{5} = \frac{145}{5} = 29 \] 2. **Calculate the Deviations from the Mean:** \[ 99 - 29 = 70, \quad 10 - 29 = -19, \quad 11 - 29 = -18, \quad 12 - 29 = -17, \quad 13 - 29 = -16 \] 3. **Square the Deviations:** \[ 70^2 = 4900, \quad (-19)^2 = 361, \quad (-18)^2 = 324, \quad (-17)^2 = 289, \quad (-16)^2 = 256 \] 4. **Sum of Squared Deviations:** \[ 4900 + 361 + 324 + 289 + 256 = 5840 \] 5. **Variance (for population):** \[ \text{Variance} = \frac{5840}{5} = 1168 \] 6. **Standard Deviation:** \[ \text{Standard Deviation} = \sqrt{1168} \approx 34.19 \] So, the standard deviation for the group of data items \( 99, 10, 11, 12, 13 \) rounded to two decimal places is **34.19**.

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