Question
upstudy study bank question image url

What is the following product? Assume \( y \geq 0 \) \( 3 \sqrt{10}\left(y^{2} \sqrt{4}+\sqrt{8 y}\right) \) \( 6 y^{2} \sqrt{10}+12 \sqrt{5 y} \) \( 6 \sqrt{10}+12 \sqrt{5 y} \) \( 6 y^{2} \sqrt{10}+4 \sqrt{5 y} \) \( 3 y^{2} \sqrt{10}+12 \sqrt{5 y} \)

Ask by Hanson Matthews. in the United States
Feb 12,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The product is \(6 \sqrt{10}y^{2} + 12 \sqrt{5y}\).

Solution

Sign in to Unlock Answers for Free!

A Learning Platform Trusted by Millions of Real Students and Teachers.

star-icon Unlock

Answered by UpStudy AI and reviewed by a Professional Tutor

Mind Expander

Let’s break down the original expression step by step to see what we can determine about it! First, simplifying what’s inside the parentheses: 1. The term \( \sqrt{4} \) simplifies to \( 2 \). 2. The term \( \sqrt{8y} \) simplifies to \( 2 \sqrt{2y} \). So the expression \( y^{2} \sqrt{4} + \sqrt{8y} \) becomes: \[ y^{2} \cdot 2 + 2 \sqrt{2y} = 2y^{2} + 2\sqrt{2y} \] Now, we can factor out a 2: \[ 2(y^{2} + \sqrt{2y}) \] Now we can go back to the original expression: \[ 3 \sqrt{10} \cdot 2(y^{2} + \sqrt{2y}) = 6\sqrt{10}(y^{2} + \sqrt{2y}) \] Distributing \( 6\sqrt{10} \) gives us: \[ 6\sqrt{10}y^{2} + 6\sqrt{20y} \] Since \( \sqrt{20} \) simplifies to \( 2\sqrt{5} \): \[ 6\sqrt{10}y^{2} + 12\sqrt{5y} \] The resulting expression is: \[ 6 y^{2} \sqrt{10} + 12 \sqrt{5 y} \] Now, when looking at the options: 1. \( 6 y^{2} \sqrt{10}+12 \sqrt{5 y} \) is a direct match. 2. The other options are incorrect representations based on our simplification. Thus, the correct product is \( 6 y^{2} \sqrt{10} + 12 \sqrt{5y} \). Remember, when simplifying expressions like this, always take it step by step to avoid missing any foundational components!

Related Questions

Latest Algebra Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy