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Systems of Equations Review solve \( \begin{array}{l}\begin{array}{l}2 x+18 y=22 \\ -x-9 y=-11\end{array} \\ \)\begin{tabular}{ll}\text { B I }\( \quad \text { u } \mid: \equiv \) \\ \hline\end{tabular}\end{array}

Ask by Griffin Stephens. in the United States
Feb 26,2025

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The system of equations has infinitely many solutions.

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Solve the system of equations \( 2x+18y=22;-x-9y=-11 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}2x+18y=22\\-x-9y=-11\end{array}\right.\) - step1: Rearrange the terms: \(2x+18y=22\) - step2: Move the expression to the right side: \(2x=22-18y\) - step3: Divide both sides: \(\frac{2x}{2}=\frac{22-18y}{2}\) - step4: Divide the numbers: \(x=11-9y\) - step5: Calculate: \(\left(x,y\right) = \left(11-9y,y\right),y \in \mathbb{R}\) - step6: Alternative Form: \(\textrm{Infinitely many solutions}\) The system of equations \(2x+18y=22\) and \(-x-9y=-11\) has infinitely many solutions. This means that the lines represented by these equations are parallel and do not intersect, resulting in an infinite number of solutions.

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To solve the system of equations, first, we can simplify one of the equations. The second equation, \(-x - 9y = -11\), can be rearranged to express \(x\) in terms of \(y\): \[ x = -9y + 11. \] Now, substitute this expression for \(x\) in the first equation \(2x + 18y = 22\): \[ 2(-9y + 11) + 18y = 22. \] This simplifies to: \[ -18y + 22 + 18y = 22. \] This shows that the equation holds for all values of \(y\), meaning the system has infinitely many solutions, which corresponds to a line. You can choose any value for \(y\), and plug it into \(x = -9y + 11\) to find a corresponding \(x\). For example, if we let \(y = 0\), we find \(x = 11\), giving us the point \((11, 0)\). Alternatively, if \(y = 1\), then \(x = 2\), giving us the point \((2, 1)\). All points of the form \(( -9y + 11, y )\) will be solutions to the original equations.

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