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10. Demonstrate and explain how to find the derivative of the following functions. Be sure to explicitly denote which derivative rules (scalar multiple, sum/difference, quotient, etc.) you are using in your work. \( \begin{array}{ll}\text { (d) } \\ g(t)=7 t^{5}-6 t^{2}-t-4\end{array} \)

Ask by Rodriquez Washington. in the United States
Feb 26,2025

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The derivative of \( g(t) = 7t^{5} - 6t^{2} - t - 4 \) is \( g'(t) = 35t^{4} - 12t - 1 \).

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We want to differentiate g(t) = 7t⁵ – 6t² – t – 4. We will use several derivative rules: 1. Power Rule: d/dt(tⁿ) = n·tⁿ⁻¹. 2. Constant Multiple Rule: d/dt[c · f(t)] = c · f '(t). 3. Sum (and Difference) Rule: The derivative of a sum/difference is the sum/difference of the derivatives. 4. Constant Rule: d/dt[c] = 0. Step-by-step: 1. Differentiate 7t⁵:   Using the Constant Multiple and Power Rules:   d/dt[7t⁵] = 7 · d/dt[t⁵] = 7 · (5t⁴) = 35t⁴. 2. Differentiate –6t²:   d/dt[–6t²] = –6 · d/dt[t²] = –6 · (2t) = –12t. 3. Differentiate –t:   Note that –t is the same as –1·t:   d/dt[–t] = –1. 4. Differentiate –4:   Since –4 is a constant, its derivative is 0. Putting it all together using the Sum/Difference Rule: g '(t) = 35t⁴ – 12t – 1 + 0 So, the derivative is:   g '(t) = 35t⁴ – 12t – 1.

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To find the derivative of the function \( g(t) = 7t^5 - 6t^2 - t - 4 \), we can use the power rule and the sum/difference rule. The power rule states that the derivative of \( t^n \) is \( n t^{n-1} \). 1. For the first term \( 7t^5 \), using the power rule, the derivative is \( 7 \cdot 5t^{5-1} = 35t^4 \). 2. For the second term \( -6t^2 \), the derivative is \( -6 \cdot 2t^{2-1} = -12t \). 3. For the third term \( -t \), the derivative is simply \( -1 \) (which can be seen as \( -1t^1 \) using the power rule). 4. The derivative of the constant \( -4 \) is \( 0 \). Putting it all together, we have: \[ g'(t) = 35t^4 - 12t - 1 \] And there you go! You've successfully used the power and sum/difference rules to find the derivative. Keep practicing, and these rules will be second nature!

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