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3. Each of three friends tlips a coin 36 tim records "tails" 20 times. Michael record 17 times. Fernanda records "tails" 23 ti a. Find the relative frequency with whi friend records "tails". b. Which friend has a relative frequen, is closest to the theoretical probabil flipping "tails" 36 times? Explain.

Ask by Carlson Bowman. in the United States
Feb 26,2025

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Answer

a. The relative frequencies are: - First friend: 20/36 ≈ 0.556 - Michael: 17/36 ≈ 0.472 - Fernanda: 23/36 ≈ 0.639 b. Michael has the relative frequency closest to the theoretical probability of 0.5.

Solution

a. To find the relative frequency for each friend, divide the number of "tails" outcomes by the total number of flips (36). • For the first friend (who got 20 tails):  Relative frequency = 20/36 ≈ 0.556 • For Michael (who got 17 tails):  Relative frequency = 17/36 ≈ 0.472 • For Fernanda (who got 23 tails):  Relative frequency = 23/36 ≈ 0.639 b. The theoretical probability of getting "tails" on a fair coin flip is 0.5. Comparing the relative frequencies:  – First friend: |0.556 – 0.5| = 0.056  – Michael: |0.472 – 0.5| = 0.028  – Fernanda: |0.639 – 0.5| = 0.139 Michael’s relative frequency (approximately 0.472) is only about 0.028 away from 0.5, making it the closest to the theoretical probability.

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To find the relative frequency for each friend: For Alex, the relative frequency of "tails" is calculated as the number of tails (20) divided by the total flips (36), giving approximately 0.56 or 56%. Michael's relative frequency is 17/36, about 0.47 or 47%. Finally, Fernanda's relative frequency is 23/36, approximately 0.64 or 64%. As for which friend is closest to the theoretical probability of 0.5 (for a fair coin), Alex's relative frequency of 56% is the closest, deviating only slightly from the expected probability! This highlights that even with a fair coin, results can vary in smaller trials.

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