Question
upstudy study bank question image url

Magnesium will combine with oxygen gas to form magnesium oxide according to the balanced equation below. \( 2 \mathrm{Mg}+\mathrm{O}_{2} \rightarrow 2 \mathrm{MgO} \) 85 grams of magnesium metal and 125 grams of oxygen gas are allowed to react. If the reaction runs to completion, which reactant will be depleted (limiting reagent) first? Oxygen Both will deplete at the same time. Magnesium More information is needed in order to answer the question.

Ask by Deleon Bowers. in the United States
Feb 25,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

Magnesium is the limiting reagent and will be depleted first.

Solution

First, determine the moles of each reactant. For magnesium (Mg): • Molar mass of Mg ≈ 24.3 g/mol • Moles of Mg = 85 g / 24.3 g/mol ≈ 3.50 moles For oxygen (O₂): • Molar mass of O₂ ≈ 32.0 g/mol • Moles of O₂ = 125 g / 32.0 g/mol ≈ 3.91 moles The balanced equation is: 2 Mg + O₂ → 2 MgO This tells us that 2 moles of magnesium react with 1 mole of oxygen. To react with 3.50 moles of magnesium, the amount of oxygen needed is: Required moles of O₂ = (3.50 moles Mg) × (1 mole O₂ / 2 moles Mg) = 1.75 moles O₂ Since there are 3.91 moles of O₂ available (which is more than the 1.75 moles required), oxygen is in excess. Thus, magnesium is the limiting reagent because it will run out before oxygen does. Answer: Magnesium

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

Beyond the Answer

To determine the limiting reagent, we first need to calculate the number of moles of each reactant. The molar mass of magnesium (Mg) is about 24.31 g/mol, so 85 grams of magnesium is approximately 3.5 moles. The molar mass of oxygen (O₂) is about 32 g/mol, so 125 grams of oxygen is about 3.9 moles. According to the balanced equation, we need 1 mole of O₂ for every 2 moles of Mg, which means we would need about 1.75 moles of O₂ to react with 3.5 moles of Mg. Since we have more than enough oxygen, magnesium will be the limiting reagent and will deplete first. This reaction is a classic in chemistry classrooms because it beautifully illustrates how stoichiometry works in real-world applications. Beyond the classroom, this type of reaction is essential in industrial settings, such as the production of magnesium oxide, which is used in refractory materials, electronics, and even as a food additive. Understanding the limiting reagent helps chemists optimize reactions in various manufacturing processes, resulting in both efficiency and cost-effectiveness!

Related Questions

Latest Chemistry Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy