Solve by completing the square. $$ j^{2}+6 j=49 $$ Write your answers as integers, proper or improper fractions in simplest form, or decir rounded to the nearest hundredth.

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Solve the equation $$ j^{2}+6j=49 $$.
Solve the quadratic equation by following steps:
- step0: Solve using the quadratic formula:
  $$j^{2}+6j=49$$
- step1: Move the expression to the left side:
  $$j^{2}+6j-49=0$$
- step2: Solve using the quadratic formula:
  $$j=\frac{-6\pm \sqrt{6^{2}-4\left(-49ight)}}{2}$$
- step3: Simplify the expression:
  $$j=\frac{-6\pm \sqrt{232}}{2}$$
- step4: Simplify the expression:
  $$j=\frac{-6\pm 2\sqrt{58}}{2}$$
- step5: Separate into possible cases:
  $$\begin{align}&j=\frac{-6+2\sqrt{58}}{2}\&j=\frac{-6-2\sqrt{58}}{2}\end{align}$$
- step6: Simplify the expression:
  $$\begin{align}&j=-3+\sqrt{58}\&j=\frac{-6-2\sqrt{58}}{2}\end{align}$$
- step7: Simplify the expression:
  $$\begin{align}&j=-3+\sqrt{58}\&j=-3-\sqrt{58}\end{align}$$
- step8: Rewrite:
  $$j_{1}=-3-\sqrt{58},j_{2}=-3+\sqrt{58}$$
The solutions to the equation $$j^{2}+6j=49$$ by completing the square are $$j_{1}=-3-\sqrt{58}$$ and $$j_{2}=-3+\sqrt{58}$$.
The solutions are $$ j = -3 - \sqrt{58} $$ and $$ j = -3 + \sqrt{58} $$.

Solve by completing the square.

Write your answers as integers, proper or improper fractions in simplest form, or decir
rounded to the nearest hundredth.

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Solve by completing the square. Write your answers as integers, proper or improper fractions in simplest form, or decir rounded to the nearest hundredth.