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39. \( \int \frac{3 e^{x}}{\sqrt[4]{e^{x}-1}} d x \) 41. \( \int \frac{\cos x d x}{2 \sin x-1} \) 64] 436. 43. \( \int \sec (5 x) d x \) 45. \( \int \sqrt{\tan x} \sec ^{2} x d x \) 47. \( \int \frac{\sin x}{\cos ^{2} x} d x \) 49. \( \int \sin x \cdot e^{\cos x} d x \) 436. 51. \( \int x \sqrt{x+3} d x \) 53. \( \int[\sin x+\cos (3 x)] d x \) 4337 5 55. \( \int \frac{d x}{x^{2}+25} \) 57. \( \int \frac{d x}{\sqrt{9-x^{2}}} \) 59. \( \int \sinh x \cosh x d x \)

Ask by Burns Morrison. in the United States
Mar 16,2025

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Here are the solutions to the integrals: 1. \( \int \frac{3 e^{x}}{\sqrt[4]{e^{x}-1}} d x = 4\sqrt[4]{(e^{x}-1)^{3}} + C \) 2. \( \int \frac{\cos x d x}{2 \sin x-1} = \frac{1}{2}\ln{(|2\sin(x)-1|)} + C \) 3. \( \int \sec (5 x) d x = \frac{1}{5}\ln{(|\sec(5x)+\tan(5x)|)} + C \) 4. \( \int \sqrt{\tan x} \sec ^{2} x d x = \frac{2}{3}\sqrt{\tan^{3}(x)} + C \) 5. \( \int \frac{\sin x}{\cos ^{2} x} d x = \sec(x) + C \) 6. \( \int \sin x \cdot e^{\cos x} d x = -e^{\cos(x)} + C \) 7. \( \int x \sqrt{x+3} d x = \frac{2}{5}x^{2}\sqrt{x+3} + \frac{2}{5}\sqrt{x+3}\times x - \frac{12}{5}\sqrt{x+3} + C \) 8. \( \int[\sin x+\cos (3 x)] d x = -\cos(x) + \frac{1}{3}\sin(3x) + C \) 9. \( \int \frac{d x}{x^{2}+25} = \frac{1}{5}\arctan\left(\frac{x}{5}\right) + C \) 10. \( \int \frac{d x}{\sqrt{9-x^{2}}} = \arcsin\left(\frac{x}{3}\right) + C \) 11. \( \int \sinh x \cosh x d x \) has an error in the input expression. If you need further assistance or corrections, please let me know!

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Extra Insights

Did you know that integrals like \( \int \frac{3 e^{x}}{\sqrt[4]{e^{x}-1}} d x \) have a fascinating historical backdrop? The concept of integration dates back to ancient civilizations, with the Greeks using geometric approaches to find areas under curves. It was not until the 17th century, with mathematicians like Newton and Leibniz, that the formal notation and methods we use today were developed, paving the way for calculus as we know it. When tackling integrals such as \( \int \sec(5x) d x \), one common mistake is forgetting to use substitution to simplify the integral. Many jump straight into integration without considering how substitution can make things easier. Always check if there's a function within the integral that, when differentiated, matches up with the other parts of the integral. This can save you from complex calculations and potential errors!

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