Use the definition of GCD, not a calculation, to complete parts (a) through (c). (a) \( \operatorname{GCD}(60,60) \) (b) \( \operatorname{GCD}(16,160) \) (c) \( \operatorname{GCD}(66,0) \) (a) \( \operatorname{GCD}(60,60)=\square \)
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The greatest common divisor (GCD) of two numbers is the largest positive integer that divides both numbers without leaving a remainder. Since both numbers in (a) are the same, the GCD of \(60\) and \(60\) is simply \(60\) because \(60\) divides itself perfectly. (b) For \( \operatorname{GCD}(16,160) \), we seek the largest positive integer that divides both \(16\) and \(160\). Since \(16\) is a factor of \(160\) (as \(160 = 16 \times 10\)), the GCD is \(16\). (c) The GCD of any number and \(0\) is the number itself, as any non-zero integer divides by \(0\) perfectly without a remainder. Therefore, \( \operatorname{GCD}(66,0) = 66\). So, to summarize: (a) \( \operatorname{GCD}(60,60) = 60 \) (b) \( \operatorname{GCD}(16,160) = 16 \) (c) \( \operatorname{GCD}(66,0) = 66 \)