A runner runs a distance of 3 km in 20 min , what is the speed \( \mathrm{in} \mathrm{m} / \mathrm{s} \) A business stocks 300 packets of beef -flavoured chips and 200 packets of tomatoe-flavourd Chips. The tomatoe -flavoured chips are not selling well, so the business decides to to decrease the number, they stock by \( 20 \% \). They also decide to increase the number of beef-flavoured chips, which are selling well, by \( 10 \% \). 1.6.1 How many packets of tomatoe chips are there after the decrease? 1.6 .2 How many packets of beef chips do they stock after the increase? A clothing store sells old stock at a \( 20 \% \) discount of its original price. If a pair of jeans now costs R160, what was its original price?

**1. Runner's Speed Calculation** - Convert distance to meters: \( 3 \text{ km} = 3000 \text{ m} \). - Convert time to seconds: \( 20 \text{ min} = 20 \times 60 = 1200 \text{ s} \). - Calculate speed using the formula: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} = \frac{3000 \text{ m}}{1200 \text{ s}} = 2.5 \text{ m/s} \] --- **2. Chips Stock Changes** *Tomato-Flavoured Chips* - Initial stock: \( 200 \) packets. - Decrease by \( 20\% \): \[ \text{Decrease Amount} = 200 \times 0.20 = 40 \text{ packets} \] - Remaining packets: \[ 200 - 40 = 160 \text{ packets} \] *Beef-Flavoured Chips* - Initial stock: \( 300 \) packets. - Increase by \( 10\% \): \[ \text{Increase Amount} = 300 \times 0.10 = 30 \text{ packets} \] - New stock: \[ 300 + 30 = 330 \text{ packets} \] --- **3. Original Price of Jeans** - Let the original price be \( x \). - A \( 20\% \) discount means the selling price is \( 80\% \) of the original price: \[ 0.80x = 160 \] - Solve for \( x \): \[ x = \frac{160}{0.80} = 200 \] --- **Final Answers:** - Runner's speed: \( 2.5 \text{ m/s} \) - Packets of tomato-flavoured chips after decrease: \( 160 \) - Packets of beef-flavoured chips after increase: \( 330 \) - Original price of the jeans: \( R200 \)