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To find out if \( \triangle ABC \) is a specific type of triangle, we can calculate the lengths of the sides. Using the distance formula \( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \), we get: - \( AB = \sqrt{(5 - 2)^2 + (4 - 3)^2} = \sqrt{3^2 + 1^2} = \sqrt{9 + 1} = \sqrt{10} \) - \( BC = \sqrt{(6 - 5)^2 + (7 - 4)^2} = \sqrt{1^2 + 3^2} = \sqrt{1 + 9} = \sqrt{10} \) - \( AC = \sqrt{(6 - 2)^2 + (7 - 3)^2} = \sqrt{4^2 + 4^2} = \sqrt{16 + 16} = \sqrt{32} = 4\sqrt{2} \) Since \( AB \) and \( BC \) are equal, but \( AC \) is different, \( \triangle ABC \) is an isosceles triangle. In mathematics, triangles can be classified not only by their sides but also by their angles! For example, an isosceles triangle may have a right angle, making it an isosceles right triangle. In this case, it’s worth exploring how the angles in a triangle relate to its sides to deepen your understanding of triangle properties and relationships!