1. find the x -intercept about \( y=x^{2}-3 x-4 \)
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The Deep Dive
To find the x-intercepts of the function \( y = x^2 - 3x - 4 \), you need to set \( y \) to zero and solve for \( x \): \[ 0 = x^2 - 3x - 4 \] Factoring gives \( (x - 4)(x + 1) = 0 \), which means the x-intercepts are \( x = 4 \) and \( x = -1 \). So, the graph of the parabola crosses the x-axis at these two points! A nifty way to visualize this is by sketching the parabola. Notice that it opens upwards (since the coefficient of \( x^2 \) is positive). This means the x-axis intercepts are where your parabola dips below the axis before coming back up, making those points \( x = 4 \) and \( x = -1 \) the places where your function is just about to take off again!