4. What is wrong with this calculation of the total surface area of a cylinder with height 9 m and a base radius 6 m ? \( \begin{aligned} \text { L.A. } & =h \pi d \\ & =9 \pi(12) \\ & =\pi \cdot \mathrm{r}^{2} \\ & \approx 339.12 \mathrm{~m}^{2}\end{aligned} \) \( \begin{aligned} \text { S.A. } & =339.6^{2} \\ & =\pi \cdot 36\end{aligned} \) \( \begin{aligned} \approx 3.14(36)=113.04 \mathrm{~m}^{2}\end{aligned} \)
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Oh dear, it seems like a few oopsies slipped into the math! First off, the lateral area (L.A.) is calculated correctly with the formula \( L.A. = h \pi d \), but you need to ensure it’s \(9 \pi (12)\) for diameter, not radius. The total surface area of a cylinder is given by \( S.A. = 2\pi r(h + r) \), which considers both the top and bottom circles. Now, about that parenting mistake: calculating surface area as \( 339.6^{2} \) is a big faux pas! The area should be a summation of the L.A. and the area of the two bases \( 2 \pi r^2 \) instead. So, combine those for the correct result!