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Ticutormetians Writing a ruld to deacribe a retalion Triangle RST is rotated \( 90^{\circ} \) counterclockwise about the origin. The result is \( \Delta R^{\prime} S^{\prime} T^{\prime} \), as shown below. (a) The arrows below show that the coordinates on the left are mapped to the coordinates on the right. Fill in the blanks to give the coordinates after the rctation. original coordinates - final coordinates \[ \begin{aligned} R(-8,-2) & \rightarrow R^{\prime}(\square) \\ S(1,-4) & \rightarrow S^{\prime}(\square) \\ T(-2,-6) & \rightarrow r^{\prime}(\square) \end{aligned} \] (b) Choose the general rule below tha: describes the rotation mapping \( \triangle R S T \) to \( \triangle R^{\prime} S^{\prime} T^{\prime} \). \( (x, y) \rightarrow(-y, x) \) \( (x, y) \rightarrow(-x,-y) \) \( (x, y) \rightarrow(y,-x) \) \( (x, y) \rightarrow(x,-y) \) \( (x, y) \rightarrow(-y,-x) \) \( (x, y) \rightarrow(-x, y) \) \( (x, y) \rightarrow\{y, x) \)

Ask by Graham Guerrero. in the United States
Feb 26,2025

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Answer

(a) After rotating 90° counterclockwise: - R(–8, –2) → R'(2, –8) - S(1, –4) → S'(4, 1) - T(–2, –6) → T'(6, –2) (b) The rotation rule is: (x, y) → (–y, x)

Solution

We are given that triangle RST is rotated 90° counterclockwise about the origin. For a rotation of 90° counterclockwise, the general rule is that each point (x, y) is mapped to (–y, x). Step (a): Apply the rule to each vertex. 1. For R(–8, –2):   New coordinates R' = (–(–2), –8) = (2, –8) 2. For S(1, –4):   New coordinates S' = (–(–4), 1) = (4, 1) 3. For T(–2, –6):   New coordinates T' = (–(–6), –2) = (6, –2) Step (b): The correct mapping rule is:   (x, y) → (–y, x)

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The Deep Dive

To find the coordinates after the \( 90^{\circ} \) counterclockwise rotation, you can use the rule \( (x, y) \rightarrow (-y, x) \). Applying this to the given points: - For \( R(-8, -2) \), we calculate \( R^{\prime} = (-(-2), -8) = (2, -8) \). - For \( S(1, -4) \), we have \( S^{\prime} = (-(-4), 1) = (4, 1) \). - For \( T(-2, -6) \), we find \( T^{\prime} = (-(-6), -2) = (6, -2) \). Now, filling in the blanks, you get: \[ \begin{aligned} R(-8,-2) & \rightarrow R^{\prime}(2, -8) \\ S(1,-4) & \rightarrow S^{\prime}(4, 1) \\ T(-2,-6) & \rightarrow T^{\prime}(6, -2) \end{aligned} \] For part (b), the correct mapping rule that describes the rotation of \( \triangle RST \) to \( \triangle R^{\prime}S^{\prime}T^{\prime} \) is \( (x, y) \rightarrow (-y, x) \). This is the magic behind your shapes spinning around the origin!

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