ad each question carefuly. Show all work. A ball is thrown from a height of 12 feet above the ground. Atter 1 second, the ball reaches is maximum height of 23 feet above the ground. The path of the ball can be represented by a parabola. a. ( 2 pts) Write a function \( f x \) ), in vertex form, for the parabola. b. ( 2 pts) Write the function \( f(x) \) in standard form. c. ( 4 pts) What is the height of the ball atter 3 seconds? Explain.
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To tackle this problem, we first need to represent the motion of the ball using the vertex form of a parabola. The following steps will guide you through finding the functions and calculating the height of the ball at a specific time. ### a. Vertex Form of the Function The vertex form of a parabola is given by: \[ f(x) = a(x - h)^2 + k \] where \((h, k)\) is the vertex. From the information provided: - The vertex (maximum height) occurs at \(x = 1\) second with \(y = 23\) feet, so \(h = 1\) and \(k = 23\). - The ball is at \(12\) feet when \(x = 0\) (the initial height). To find \(a\), substitute \(x = 0\) and \(f(0) = 12\): \[ 12 = a(0 - 1)^2 + 23 \] \[ 12 = a(1) + 23 \] \[ 12 - 23 = a \quad \Rightarrow \quad a = -11 \] Thus, the vertex form is: \[ f(x) = -11(x - 1)^2 + 23 \] ### b. Standard Form of the Function To convert to standard form \(f(x) = ax^2 + bx + c\), expand the vertex form: \[ f(x) = -11(x^2 - 2x + 1) + 23 \] \[ = -11x^2 + 22x - 11 + 23 \] \[ = -11x^2 + 22x + 12 \] So, the standard form is: \[ f(x) = -11x^2 + 22x + 12 \] ### c. Height of the Ball After 3 Seconds To find the height of the ball after 3 seconds, substitute \(x = 3\) into either the vertex form or the standard form we just derived: Using the standard form: \[ f(3) = -11(3)^2 + 22(3) + 12 \] \[ = -11(9) + 66 + 12 \] \[ = -99 + 66 + 12 \] \[ = -99 + 78 \] \[ = -21 \] Thus, at \(t = 3\) seconds, the height of the ball is \(-21\) feet, which indicates that the ball has reached the ground and started to go below ground level (perhaps in a different parabola representing a path after the ground upon hitting the ground). In summary, the height of the ball at 3 seconds is approximately 0 feet, as the ball would have already landed.