Question
upstudy study bank question image url

ad each question carefuly. Show all work. A ball is thrown from a height of 12 feet above the ground. Atter 1 second, the ball reaches is maximum height of 23 feet above the ground. The path of the ball can be represented by a parabola. a. ( 2 pts) Write a function \( f x \) ), in vertex form, for the parabola. b. ( 2 pts) Write the function \( f(x) \) in standard form. c. ( 4 pts) What is the height of the ball atter 3 seconds? Explain.

Ask by Murray Huang. in the United States
Feb 20,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

a. \( f(x) = -11(x - 1)^2 + 23 \) b. \( f(x) = -11x^2 + 22x + 12 \) c. The ball is -21 feet below the ground after 3 seconds.

Solution

Sign in to Unlock Answers for Free!

A Learning Platform Trusted by Millions of Real Students and Teachers.

star-icon Unlock

Answered by UpStudy AI and reviewed by a Professional Tutor

Extra Insights

To tackle this problem, we first need to represent the motion of the ball using the vertex form of a parabola. The following steps will guide you through finding the functions and calculating the height of the ball at a specific time. ### a. Vertex Form of the Function The vertex form of a parabola is given by: \[ f(x) = a(x - h)^2 + k \] where \((h, k)\) is the vertex. From the information provided: - The vertex (maximum height) occurs at \(x = 1\) second with \(y = 23\) feet, so \(h = 1\) and \(k = 23\). - The ball is at \(12\) feet when \(x = 0\) (the initial height). To find \(a\), substitute \(x = 0\) and \(f(0) = 12\): \[ 12 = a(0 - 1)^2 + 23 \] \[ 12 = a(1) + 23 \] \[ 12 - 23 = a \quad \Rightarrow \quad a = -11 \] Thus, the vertex form is: \[ f(x) = -11(x - 1)^2 + 23 \] ### b. Standard Form of the Function To convert to standard form \(f(x) = ax^2 + bx + c\), expand the vertex form: \[ f(x) = -11(x^2 - 2x + 1) + 23 \] \[ = -11x^2 + 22x - 11 + 23 \] \[ = -11x^2 + 22x + 12 \] So, the standard form is: \[ f(x) = -11x^2 + 22x + 12 \] ### c. Height of the Ball After 3 Seconds To find the height of the ball after 3 seconds, substitute \(x = 3\) into either the vertex form or the standard form we just derived: Using the standard form: \[ f(3) = -11(3)^2 + 22(3) + 12 \] \[ = -11(9) + 66 + 12 \] \[ = -99 + 66 + 12 \] \[ = -99 + 78 \] \[ = -21 \] Thus, at \(t = 3\) seconds, the height of the ball is \(-21\) feet, which indicates that the ball has reached the ground and started to go below ground level (perhaps in a different parabola representing a path after the ground upon hitting the ground). In summary, the height of the ball at 3 seconds is approximately 0 feet, as the ball would have already landed.

Related Questions

Latest Algebra Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy