Use the given conditions to write an equation for the line in point-slope form and slope-intercept form. Passing through \( (-5,-2) \) and \( (5,12) \) Type the point-slope form of the equation of the line. \( \square \) (Use integers or simplified fractions for any numbers in the equation.) Type the slope-intercept form of the equation of the line. \( \square \) Use integers or simplified fractions for any numbers in the equation.)
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To find the equation of the line passing through the points \((-5,-2)\) and \((5,12)\), we first need to calculate the slope \(m\) using the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{12 - (-2)}{5 - (-5)} = \frac{12 + 2}{5 + 5} = \frac{14}{10} = \frac{7}{5}. \] Now, using the point-slope form \(y - y_1 = m(x - x_1)\) with point \((-5, -2)\), we have: \[ y - (-2) = \frac{7}{5}(x - (-5)), \] which simplifies to: \[ y + 2 = \frac{7}{5}(x + 5). \] For the slope-intercept form, we start with the equation from point-slope form and solve for \(y\): \[ y + 2 = \frac{7}{5}x + \frac{7}{5} \cdot 5, \] \[ y + 2 = \frac{7}{5}x + 7, \] \[ y = \frac{7}{5}x + 7 - 2, \] \[ y = \frac{7}{5}x + 5. \] So the answers are: Point-slope form: \(y + 2 = \frac{7}{5}(x + 5)\) Slope-intercept form: \(y = \frac{7}{5}x + 5\)