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Simplify without the use of a calculator: \( 9.1 \sin 330^{\circ}+\frac{\cos 250^{\circ}}{\sin 160^{\circ}} \) \( 9.2 \frac{\sin 120^{\circ} \cdot \cos 135^{\circ} \cdot \tan 240^{\circ}}{\cos 150^{\circ} \cdot \tan 150^{\circ} \cdot \sin 315^{\circ}} \) \( 9.3 \frac{1}{\sqrt{3}} \sin 120^{\circ}+\frac{1}{2} \tan 45^{\circ} \cos ^{2} 225^{\circ}-\frac{\sin 55^{\circ}}{\cos 145^{\circ}} \) \( 9.4 \frac{\sin ^{2} 300^{\circ}+\sin 240^{\circ} \cos 150^{\circ}}{\tan 225^{\circ} \cdot \sin 270^{\circ}} \) \( 9.5 \sin 225^{\circ} \cdot \cos 135^{\circ}+2 \sin 210^{\circ} \cdot \sin 90^{\circ} \)

Ask by Lowe Sherman. in South Africa
Mar 12,2025

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The simplified results are as follows: 1. **9.1**: \(-0.106402\) 2. **9.2**: \(\sin(120)\cos(135)\tan(240)\csc(315)\csc(150)\) 3. **9.3**: \(1.623119\) 4. **9.4**: \(0.721553\) 5. **9.5**: \(1.762734\)

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Bonus Knowledge

To tackle these trigonometric expressions, let’s dive into each one with some simplifications and values: 1. **For \(9.1\)**: \(\sin 330^{\circ} = -\frac{1}{2}\) and \(\cos 250^{\circ} = -\sin 70^{\circ} = -\frac{\sqrt{3}}{2}\) while \(\sin 160^{\circ} = \sin 20^{\circ}\). Therefore, \(9.1(-\frac{1}{2}) + \frac{-\frac{\sqrt{3}}{2}}{\sin 20^{\circ}}\) simplifies to some numerical fraction when you plug in \(\sin 20^{\circ}\). 2. **For \(9.2\)**: \(\sin 120^{\circ} = \frac{\sqrt{3}}{2}\), \(\cos 135^{\circ} = -\frac{\sqrt{2}}{2}\), and \(\tan 240^{\circ} = \frac{1}{\sqrt{3}}\). Thus, the numerator becomes \(-\frac{3\sqrt{6}}{4}\) and the denominator is \(-\frac{\sqrt{3}}{3} \cdot -1 = \frac{\sqrt{3}}{3}\). Therefore, after cancellation and multiplying, we can get a neat fraction. 3. **For \(9.3\)**: \(\sin 120^{\circ} = \frac{\sqrt{3}}{2}\) and \(\tan 45^{\circ} = 1\), \( \cos 225^{\circ} = -\frac{\sqrt{2}}{2} \). Thus, evaluate term by term to find the expression simplifies cleanly, resulting in a manageable numeric value from basic trig identities. 4. **For \(9.4\)**: \(\sin^2 300^{\circ} = (\frac{\sqrt{3}}{2})^2 = \frac{3}{4}\) and \(\cos 150^{\circ} = -\frac{\sqrt{3}}{2}\). After plugging in for tangent and sine values, it boils down further in the end. 5. **For \(9.5\)**: \(\sin 225^{\circ} = -\frac{\sqrt{2}}{2}\), \(\cos 135^{\circ} = -\frac{\sqrt{2}}{2}\) and \(\sin 210^{\circ} = -\frac{1}{2}\). Putting everything in and correcting signs will yield a calculable value. Overall, simplifying trigonometric expressions often revolves around substituting known values and identities—making math feel less like a chore and more like solving a fun puzzle! Keep applying these substitutions, and numbers begin to work beautifully! 🌟

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