4. \( \begin{array}{l}7 \frac{8}{12} \\ -2 \frac{3}{12} \\ \text { 8. } 5 \frac{2}{8}-3 \frac{7}{8}\end{array} \)

Let's solve the problems step by step. ### Problem 1: \( 7 \frac{8}{12} - 2 \frac{3}{12} \) 1. **Convert mixed numbers to improper fractions:** - For \( 7 \frac{8}{12} \): \[ 7 \frac{8}{12} = \frac{7 \times 12 + 8}{12} = \frac{84 + 8}{12} = \frac{92}{12} \] - For \( 2 \frac{3}{12} \): \[ 2 \frac{3}{12} = \frac{2 \times 12 + 3}{12} = \frac{24 + 3}{12} = \frac{27}{12} \] 2. **Subtract the improper fractions:** \[ \frac{92}{12} - \frac{27}{12} = \frac{92 - 27}{12} = \frac{65}{12} \] 3. **Convert back to a mixed number:** \[ \frac{65}{12} = 5 \frac{5}{12} \] ### Problem 2: \( 5 \frac{2}{8} - 3 \frac{7}{8} \) 1. **Convert mixed numbers to improper fractions:** - For \( 5 \frac{2}{8} \): \[ 5 \frac{2}{8} = \frac{5 \times 8 + 2}{8} = \frac{40 + 2}{8} = \frac{42}{8} \] - For \( 3 \frac{7}{8} \): \[ 3 \frac{7}{8} = \frac{3 \times 8 + 7}{8} = \frac{24 + 7}{8} = \frac{31}{8} \] 2. **Subtract the improper fractions:** \[ \frac{42}{8} - \frac{31}{8} = \frac{42 - 31}{8} = \frac{11}{8} \] 3. **Convert back to a mixed number:** \[ \frac{11}{8} = 1 \frac{3}{8} \] ### Final Answers: 1. \( 7 \frac{8}{12} - 2 \frac{3}{12} = 5 \frac{5}{12} \) 2. \( 5 \frac{2}{8} - 3 \frac{7}{8} = 1 \frac{3}{8} \)