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(1) \( \frac{25^{-5} \cdot 15^{x+1}}{3^{x} \cdot 5^{-5}} \) 2) \( (3 m-2 n)(m+2 n-5) \)

Ask by Sherman Lambert. in South Africa
Mar 18,2025

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Answer

1) \( 3 \cdot 5^{x - 4} \) 2) \( 3m^2 + 4mn - 15m - 4n^2 + 10n \)

Solution

Simplify the expression by following steps: - step0: Multiply the terms: \(\left(3m-2n\right)\left(m+2n-5\right)\) - step1: Apply the distributive property: \(3m\times m+3m\times 2n-3m\times 5-2nm-2n\times 2n-\left(-2n\times 5\right)\) - step2: Multiply the terms: \(3m^{2}+6mn-15m-2nm-4n^{2}-\left(-10n\right)\) - step3: Remove the parentheses: \(3m^{2}+6mn-15m-2nm-4n^{2}+10n\) - step4: Subtract the terms: \(3m^{2}+4mn-15m-4n^{2}+10n\) Calculate or simplify the expression \( \frac{25^{-5} \cdot 15^{x+1}}{3^{x} \cdot 5^{-5}} \). Simplify the expression by following steps: - step0: Solution: \(\frac{25^{-5}\times 15^{x+1}}{3^{x}\times 5^{-5}}\) - step1: Factor the expression: \(\frac{5^{-10}\times 15^{x+1}}{3^{x}\times 5^{-5}}\) - step2: Reduce the fraction: \(\frac{15^{x+1}}{3^{x}\times 5^{5}}\) - step3: Factor the expression: \(\frac{3^{x+1}\times 5^{x+1}}{3^{x}\times 5^{5}}\) - step4: Reduce the fraction: \(3\times 5^{x-4}\) Let's break down the solutions for both expressions step by step. ### 1) Simplifying \( \frac{25^{-5} \cdot 15^{x+1}}{3^{x} \cdot 5^{-5}} \) **Step 1: Rewrite the bases.** - \( 25 = 5^2 \), so \( 25^{-5} = (5^2)^{-5} = 5^{-10} \). - \( 15 = 3 \cdot 5 \), so \( 15^{x+1} = (3 \cdot 5)^{x+1} = 3^{x+1} \cdot 5^{x+1} \). **Step 2: Substitute back into the expression.** \[ \frac{5^{-10} \cdot (3^{x+1} \cdot 5^{x+1})}{3^{x} \cdot 5^{-5}} = \frac{3^{x+1} \cdot 5^{-10 + x + 1}}{3^{x} \cdot 5^{-5}} \] **Step 3: Simplify the powers of 5.** \[ = \frac{3^{x+1}}{3^{x}} \cdot 5^{-10 + x + 1 + 5} = 3^{(x+1) - x} \cdot 5^{-4 + x} = 3^{1} \cdot 5^{x - 4} \] **Final Result:** \[ 3 \cdot 5^{x - 4} \] ### 2) Expanding \( (3 m-2 n)(m+2 n-5) \) **Step 1: Use the distributive property (FOIL method).** - First: \( 3m \cdot m = 3m^2 \) - Outer: \( 3m \cdot 2n = 6mn \) - Inner: \( -2n \cdot m = -2mn \) - Last: \( -2n \cdot -5 = 10n \) **Step 2: Combine like terms.** \[ 3m^2 + 6mn - 2mn + 10n = 3m^2 + (6mn - 2mn) + 10n = 3m^2 + 4mn + 10n \] **Final Result:** \[ 3m^2 + 4mn - 15m - 4n^2 + 10n \] ### Summary of Results: 1) \( \frac{25^{-5} \cdot 15^{x+1}}{3^{x} \cdot 5^{-5}} = 3 \cdot 5^{x - 4} \) 2) \( (3 m-2 n)(m+2 n-5) = 3m^2 + 4mn - 15m - 4n^2 + 10n \)

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Mind Expander

Did you know that exponents have their roots in ancient civilizations? The Babylonian mathematicians were the pioneers of using powers long before we formalized them. They employed a base-60 number system, which shows how creative humans can be with numerical representations! Today, we use exponents in everything from finance to physics—talk about an enduring legacy! When solving polynomial expressions like \( (3m - 2n)(m + 2n - 5) \), it’s helpful to remember the distributive property or FOIL method. A classic mistake here is to forget to multiply each term correctly. Just like a recipe, all ingredients must be properly combined for the best outcomes—so take your time and keep track of each term to avoid any flavorless mishaps!

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