Question
s.15 compare ratesimord problems Nic Dean and Lisa both found deals online for movie tickets. Dean bought 4 movie tickets for \( \$ 3980 \). Lisa bought 6 movie tickets for \( \$ 46.50 \). How much more did Dean pay per ticket than Lisa? \( \$ \) per ticket
Ask by Ball Byrd. in the United States
Feb 28,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
Dean paid $2.20 more per ticket than Lisa.
Solution
First, find the cost per ticket for each deal.
• For Dean:
He paid $39.80 for 4 tickets. Dividing,
Cost per ticket = 39.80 ÷ 4 = 9.95 dollars.
• For Lisa:
She paid $46.50 for 6 tickets. Dividing,
Cost per ticket = 46.50 ÷ 6 = 7.75 dollars.
Now, subtract Lisa’s per‐ticket cost from Dean’s:
Difference = 9.95 − 7.75 = 2.20 dollars.
Dean paid $2.20 more per ticket than Lisa.
Answered by UpStudy AI and reviewed by a Professional Tutor
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Simplify this solution Beyond the Answer
To find out how much more Dean paid per ticket than Lisa, we first need to calculate the price per ticket for both Dean and Lisa. For Dean: The total cost for 4 tickets is \( \$ 3980 \). Thus, the price per ticket for Dean is: \[ \text{Price per ticket for Dean} = \frac{3980}{4} = \$ 995 \] For Lisa: The total cost for 6 tickets is \( \$ 46.50 \). Thus, the price per ticket for Lisa is: \[ \text{Price per ticket for Lisa} = \frac{46.50}{6} = \$ 7.75 \] Now, we subtract Lisa's price per ticket from Dean's price per ticket: \[ \text{Difference} = 995 - 7.75 = 987.25 \] So, Dean paid \( \$ 987.25 \) more per ticket than Lisa.
