Question
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Evaluate the expression if \( x=3, y=-7 \), and \( z=3 \). \( (-2+x)(-1+y)(3-z) \) Select the correct choice below and fill in any answer boxes within your choice. A. \( (-2+x)(-1+y)(3-z)= \) B. The answer is undefined.

Ask by Lambert Lane. in the United States
Mar 08,2025

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Tutor-Verified Answer

Answer

A. \((-2+x)(-1+y)(3-z)= 0\)

Solution

1. Substitute the given values into the expression: \[ (-2+x)(-1+y)(3-z) \quad \text{with} \quad x=3,\, y=-7,\, z=3. \] 2. Evaluate each factor: \[ -2+x = -2+3 = 1, \] \[ -1+y = -1+(-7) = -8, \] \[ 3-z = 3-3 = 0. \] 3. Multiply the factors together: \[ 1 \cdot (-8) \cdot 0 = 0. \] A. \((-2+x)(-1+y)(3-z)= 0\)

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First, substitute the values of \( x \), \( y \), and \( z \) into the expression: \[ (-2+3)(-1-7)(3-3) \] Now, simplify each part: 1. \( -2 + 3 = 1 \) 2. \( -1 - 7 = -8 \) 3. \( 3 - 3 = 0 \) Now putting it all together: \[ (1)(-8)(0) \] Since anything multiplied by zero is zero, the final answer is: \[ (-2+x)(-1+y)(3-z) = 0 \] So the correct choice is: A. \( (-2+x)(-1+y)(3-z)= 0 \)

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