Question
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1. \( \begin{array}{l}y=-\frac{3}{2} x+5 \\ y=-\frac{2}{3} x+5\end{array} \)

Ask by West Hilton. in the United States
Mar 09,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The solution is \( (0, 5) \).

Solution

1. Set the two expressions for \( y \) equal to each other: \[ -\frac{3}{2}x + 5 = -\frac{2}{3}x + 5 \] 2. Subtract \( 5 \) from both sides: \[ -\frac{3}{2}x = -\frac{2}{3}x \] 3. Multiply both sides by the common denominator \( 6 \) to eliminate fractions: \[ 6\left(-\frac{3}{2}x\right) = 6\left(-\frac{2}{3}x\right) \] which simplifies to: \[ -9x = -4x \] 4. Add \( 9x \) to both sides: \[ 0 = 5x \] 5. Solve for \( x \): \[ x = 0 \] 6. Substitute \( x = 0 \) into one of the original equations, for example: \[ y = -\frac{3}{2}(0) + 5 = 5 \] The solution to the system is: \[ (x, y) = (0, 5) \]

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Simplify this solution

Beyond the Answer

These two equations represent linear functions with interesting characteristics. The first line, \(y = -\frac{3}{2}x + 5\), has a steep negative slope, indicating it declines sharply as x increases, while the second line, \(y = -\frac{2}{3}x + 5\), has a more gradual negative slope. Intriguingly, both lines share the same y-intercept at (0, 5). This means they cross the y-axis at the same point but spread apart as x moves away from 0. To find the intersection point of these two lines, we need to set them equal to each other: \(-\frac{3}{2}x + 5 = -\frac{2}{3}x + 5\). Simplifying this will reveal whether they intersect or if they are parallel. As the slopes are different, they will indeed intersect somewhere on the Cartesian plane—just a little peak of where they blend together! Happy solving!

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