A box is at rest on a rough surface. It experiences a normal force of magnitude 655 N . The magnitude of the maximum static frictional force \( \left(f_{\mathrm{s}}^{\max }\right) \) is 393 N . What is the coefficient of static friction ( \( \left.\mu_{\mathrm{s}}\right) \) ?

To find the coefficient of static friction (\(\mu_{\mathrm{s}}\)), you can use the formula: \[ f_{\mathrm{s}}^{\max} = \mu_{\mathrm{s}} \cdot N \] where \(N\) is the normal force. Rearranging the formula gives: \[ \mu_{\mathrm{s}} = \frac{f_{\mathrm{s}}^{\max}}{N} \] Substituting the values provided: \[ \mu_{\mathrm{s}} = \frac{393\, \text{N}}{655\, \text{N}} \approx 0.600 \] So, the coefficient of static friction (\(\mu_{\mathrm{s}}\)) is approximately 0.600.