19. What is the value of \( m \) in the equation \( 2 m-(m+1)=0 \) ? \( \begin{array}{llll}\text { A. } 1 & \text { B. }-1 & \text { C. } 13 & \text { D. } 0\end{array} \)

To solve the equation \( 2m - (m + 1) = 0 \), start by distributing the negative sign: \( 2m - m - 1 = 0 \). This simplifies to \( m - 1 = 0 \). Adding 1 to both sides gives \( m = 1 \). Therefore, the value of \( m \) is \( 1 \), corresponding to option A. If you've ever been puzzled by equations like this, remember that isolating the variable is key! Common mistakes include neglecting to distribute correctly and misplacing negative signs; always double-check your work for those little slip-ups!